NEET Practice Questions

Hint: \(E = \frac{d(\phi)}{dt}\)

Step:

Find the induced emf in the coil.
The magnetic flux linked with a coil of wire having \(N\) turns and the area of the coil is \(A\), is given by;\(\phi = NBA\), where magnetic field is varying with time. 
Induced emf in the coil is given by \(E = \frac{d(NBA)}{dt} \Rightarrow E = NA \frac{dB}{dt}. \)
Hence, option (2) is the correct answer.
 

Hint: \(Q = ms \Delta T\)

Step: Find the specific heat.
 \(Q= ms \Delta T~~~…(1)\)
\(i=\dfrac{dQ}{dt}=\text{constant}\)
now, from equation \((1)\) we will get
\(\dfrac{dQ}{dt}=ms\left(\dfrac{d T}{dt}\right)\)
\(\dfrac{i}{ms}=\dfrac{dT}{dt}\)
\(\Rightarrow\dfrac{d T}{dt} = \text{slope of the graph}\propto \dfrac{1}{ms}\)
Therefore, the more of the specific heat, the lesser the slope; the lesser of the specific heat, the more of the slope.
Hence, option (2) is the correct answer.
 

Hint: Consider dipoles as bar magnets.

Step 1: Analyze the configuration \((A)\).
This configuration is analogous to two bar magnets on a straight line, with the north poles of both magnets facing right. In this case, the magnets will attract each other.
 

Step 2: Analyze the configuration \((B)\).
This configuration is analogous to two bar magnets on a straight line, with the north poles of both magnets aligned in opposite directions, as shown in the figure. In this case, the magnets will repel each other.
 
Hence, option (1) is the correct answer.
 

Hint: The acid-base pair that differs only by one proton is called a conjugate acid-base pair.
 

 

Hint: RNA is a nucleotide.

Explanation: 

(i) RNA is a nucleic acid that is composed of nucleotides. Each RNA nucleotide consists of a nitrogenous base (adenine, guanine, cytosine, or uracil), a ribose sugar, and a phosphate group.

(ii) RNA hydrolysis is a reaction in which a phosphodiester bond in the sugar-phosphate backbone of RNA is broken, cleaving the RNA molecule. RNA is susceptible to this base-catalyzed hydrolysis because the ribose sugar in RNA has a hydroxyl group at the 2′ position.

The complete hydrolysis of DNA yields β-D-2-deoxyribose, phosphoric acid, and nitrogen-containing heterocyclic compounds.

So, option 3 is the correct answer.
 

Ammonium phosphomolybdate is
\(\left({NH_{4}}\right)_3PO_{4}.12MoO_{3}\)
Oxidation state of Mo
\(\underset{\left({{NH}_{4}^{{+}}}\right)}{{3}\left({{+}{1}}\right)}{+}\underset{{PO}_{4}^{{3}{-}}}{\left({{-}{3}}\right)}{+}\underset{Mo}{12x}{+}\underset{Oxygen}{{36}\left({{-}{2}}\right)}{=}{0}\)
Calculation gives x = +6