Hint: \({\Delta}{Q}={\Delta}{W}\) for a cyclic process.
Step: Find the heat absorbed by the system in the given cyclic process.
The work done by the gas during the cyclic process is given by;
\(W = \pi ab\)
\(\Rightarrow W = \pi[10\times 10^{3}\times 10\times 10^{-3}]\)
\(\Rightarrow W = 100\pi ~\text{J}\)
The heat absorbed by the system in the given cyclic process is given by;
\(\Delta Q ={W}=100\pi~\text{J}= 10^{2}\pi ~\text{J}~~~~~[\Delta U =0]\)
Hence, option (2) is the correct answer.
