The p-Block Elements (XI)

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Q1.

Match the species in Column-I with their corresponding hybridisation in Column-II:

	Column-I (Species)		Column-II (Hybridisation)
A.	Boron in ${[B {(OH)}_{4}]}^{-}$	i.	sp²
B.	Aluminium in ${[Al {(H_{2} O)}_{6}]}^{3 +}$	ii.	sp³
C.	Carbon in Buckminsterfullerene	iii.	sp³d²
D.	Germanium in ${[{GeCl}_{6}]}^{2 -}$

Explanation:

Hint: The hybridization of boron in [ B(OH)₄ ]^–

A. The hybridization of Boron in

{[B {(OH)}_{4}]}^{-}

is sp³ hybridised.

B. The hybridization of aluminium in

{[Al {(H_{2} O)}_{6}]}^{3 +}

is sp³d² hybridised.

C. The hybridization of carbon in Buckminster fullerene is sp² hybridised.The fourth electron remains free and responsible for its conductivty

D. The hybridization of germanium in

{[{GeCl}_{6}]}^{2 -}

is sp³d² hybridised.

Q2. In the reaction given below, the product “X” is :
$\mathrm{Na_2B_4O_7\xrightarrow{\text{ heat }~~}X+NaBO_2 }$