Q111. The speed of light in vacuum is taken as unity. If light takes $6$ min $40$ s to reach the Earth from the Sun, the distance between the Sun and the Earth in a new unit is:
- $3 \times 10^8$
- $3 \times 10^{10}$
- $400$
- $500$
Explanation:
Hint: Convert time into seconds; since speed distance equals time directly.
Step: Find the distance between the Sun and the Earth in a new unit.
The Speed of light is given as , so distance covered is given by time taken.
The time taken by the light is min s = .
The distance between the sun and earth in new unit is
Hence, option (3) is the correct answer.
#592764
Exam: NEET – 2026
Q112.
Given below are two statements:
| Statement I: |
Image formation needs regular reflection and/or refraction. |
| Statement II: |
The variety in colour of objects we see around us is due to the constituent colours of the light incident on them. |
- Statement I is correct but Statement II is incorrect.
- Statement I is incorrect but Statement II is correct.
- Both Statement I and Statement II are correct.
- Both Statement I and Statement II are incorrect.
Explanation:
Hint: Recall the concept of Reflection and refraction of the light.
Explanation:
Statement I: Image formation needs regular reflection and/or refraction.
This statement is correct. Image formation relies on the interaction of light with surfaces. Here’s how:
Regular Reflection: This occurs when parallel rays of light strike a smooth surface and reflect back in a parallel manner. Mirrors are a prime example of regular reflection. This type of reflection allows for clear, focused images.
Refraction: This occurs when light passes from one medium to another (like from air to water or air to glass). The change in speed causes the light to bend, resulting in image formation. This is how lenses in cameras, telescopes, and our own eyes work.
Statement II: The variety in colour of objects we see around us is due to the constituent colours of the light incident on them.
This statement is also correct. The colors we perceive are based on the interaction between light and objects:
White Light: Sunlight or light from a bulb contains all the colors of the rainbow (the visible spectrum).
Selective Absorption: Objects absorb certain colors of light and reflect others. For instance, a red apple absorbs most colors except red, which it reflects back to our eyes.
Pigments: Many objects, especially those we paint or dye, contain pigments that absorb specific colors and reflect others.
Hence, option (3) is the correct answer.
#468806
Exam: NEET – 2024
Q113. The time taken by sunlight to pass through a glass slab of thickness $5~\text{mm}$ and refractive index $1.5$ is:
- $\left(\dfrac{5}{3}\right) \times 10^{-8}~\text{s}$
- $\left(\dfrac{5}{2}\right) \times 10^{-11}~\text{s}$
- $\left(\dfrac{5}{3}\right) \times 10^{-11}~\text{s}$
- $\left(\dfrac{5}{2}\right)\times 10^{-8}~\text{s}$
Explanation:
Hint: μ=cv
Step: Find the time taken by the sunlight to pass through a glass slab.
The time taken by the sunlight to pass through a glass slab is given by;
t=optical path lengthspeed of light
⇒t=μ×Lc=1.5×5×10−33×108=(52)×10−11 s [L=5 mm]
Hence, option (2) is the correct answer.
#456797
Exam: NEET – 2024
Q114. The graph that shows the correct variation of $\dfrac{1}{v}$ with $\dfrac{1}{u}$ for a concave mirror, where $u$ is the object distance and $v$ is the image distance, is:
Explanation:
Hint: 1v+1u=1f
Step: Find the correct variation of 1v with 1u for a concave mirror.
According to the mirror equation:
1v+1u=1f
⇒1v=−1u+1f ...(1) [f=−ve, for concave mirror]
Equation (1) represents a straight line having a negative slope and negative intercept.
Therefore, the correct graph is shown below;

Hence, option (2) is the correct answer.
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Exam: NEET – 2024
Q115. For a prism, when the light undergoes minimum deviation, the relationship between the angle of incidence $(i)$ and the angle of emergence $(i’)$ is:
- $i=i’$
- $i>i’$
- $i<i’$
- $i=0$
Explanation:
Hint: i=e which implies r1=r2.
Step: Find the relation between the angles i and i′.
The angle of incidence i and angle of emergence i′ on the prism is shown in the figure below;

For the minimum angle of deviation;
i=i′
⇒r1=r2
Therefore, the correct relation between the angles is i=i′.
Hence, option (1) is the correct answer.
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Exam: NEET – 2024
Q116. A small telescope has an objective of focal length $140~\text{cm}$ and an eyepiece of focal length $5.0~\text{cm}.$ The magnifying power of the telescope for viewing a distant object is:
Explanation:
Hint: m=f0fe
Step: Find the magnifying power of the telescope for viewing a distant object.
Given: f0=140 cm,fe=5 cm
The magnifying power of a telescope for viewing a distant object is given by;
m=f0fe
⇒m=1405=28
Therefore, the magnifying power of the telescope is 28.
Hence, option (1) is the correct answer.
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Exam: NEET – 2024
Q117. A light ray enters through a right-angled prism at point
$P$ with the angle of incidence
$30^\circ$ as shown in the figure. It travels through the prism parallel to its base
$BC$ and emerges along the face
$AC.$ The refractive index of the prism is:

- ${\dfrac{\sqrt5}{2}}$
- ${\dfrac{\sqrt3}{4}}$
- ${\dfrac{\sqrt3}{2}}$
- ${\dfrac{\sqrt5}{4}}$
Explanation:
Hint: Apply Snell’s law.
Step: Find the refractive index of the prism.
Given: A=90∘
Let the refractive index of the prism is μ.
A=r1+r2
⇒r2=90∘−r1
Apply Snell’s law at point P
1×sin30∘=μsinr1⇒μsinr1=12 ...(1)
Apply Snell’s law at point Q
μ×sinr2=1sin90∘⇒μsinr2=1⇒μsin(90−r1)=1
⇒μcosr1=1 ...(2)
Squaring and adding equations (1) and (2) we get;
μ2=1+14=54
⇒μ=√52
Therefore, the refractive index of the prism is √52.
Hence, option (1) is the correct answer.
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Exam: NEET – 2024
Q118. In a certain camera, a combination of four similar thin convex lenses are arranged axially in contact. Then the power of the combination and the total magnification in comparison to the power $( p )$ and magnification $( m )$ for each lens will be, respectively –
- $4 p$ and $m^4$
- $p^4$ and $m^4$
- $4 p$ and $4 m$
- $p^4$ and $4 m$
Exam: NEET – 2025
Q119. A microscope has an objective of focal length $2~\text{cm},$ eyepiece of focal length $4~\text{cm}$ and the tube length of $40~\text{cm}.$ If the distance of distinct vision of eye is $25~\text{cm},$ the magnification in the microscope is:
Exam: NEET – 2025
Q120. A ray of monochromatic light is passing through an equilateral prism
$(ABC)$ as shown in the figure. The refracted ray
$(QR)$ is parallel to its base
$(BC)$ and the angle of incidence
$(i)$ is
$50^\circ$ . Then the angle of deviation
$(\delta)$ is:

- $40^\circ$
- $45^\circ$
- $55^\circ$
- $35^\circ$
Explanation:
Hint: δmin=i+e−A
Step: Find the angle of deviation.
The deviation in the prism is given by;
δ=i+e−A
Where, A=r1+r2, since the path is symmetric ((r1=r2)) so, the angle of incidence is equal to angle of emergence i.e., i=e=50∘
Therefore, the angle of deviation is given by;
⇒δ=50∘+50∘−60∘=40∘
Hence, option (1) is the correct answer.
#592783
Exam: NEET – 2026