Ethers: Preparation & Properties, Uses CH3 — O — CH(CH3)2 + HI → B (Product) The product ‘B’ in the above mentioned reaction is- CH3OH + (CH3)2CHl lCH2OCH(CH3)2 CH3OC(CH3)2 CH3l + (CH3)2CHOH Explanation: Hint: Reaction follows SN1 mechanism. The mechanism of the reaction is shown below: Because of the large size of the iodide, it approaches the smaller alkyl group to avoid steric hindrance in case of unsymmetrical ether. Hence, alkyl halide is formed from a smaller alkyl group in unsymmetrical ether. Hence, option 4th is the correct answer. #94033 Exam: AIPMT – 2006 … AIPMT - 2006